 |
 |
 |
 |
The puzzles are marked with stars ( ) that show the degree of difficulty of the given puzzle. |  |
| back to the main page
| |
| Copyright © 1996-2013. RJE-productions. All rights reserved. No part of this website may be published, in any form or by any means, without the prior permission of the authors.
| |
 |
Eureka!   
|  |
|  |
|
There is a story that Archimedes, the Greek mathematician,
was asked to find out if the new golden crown of the king was made of pure gold,
while keeping the crown intact.
Sitting in a public bath and thinking about it, Archimedes noticed the displacement of
the water caused by sinking his body lower into the water.
He suddenly realized that he had found the solution: if the crown was made of pure gold,
it should displace the same volume of water as a bar of pure gold with an equal weight.
Excited, he jumped out of the bath and ran home shouting "Eureka!" ("I've found it!"),
forgetting that he was still naked...
We do not know if the story is true. But we do know that Archimedes discovered the first law of hydrostatics:
when a body is immersed in a fluid, it experiences an upward buoyant force which is equal to the weight of the fluid displaced by the immersed part of the body.
Can you solve the following questions, and have your "Eureka!" moments, using this famous law?
In an aquarium filled with water, a block of ice floats.
We mark the current water level.
|  |
 |
The Question:
When the ice has molten completely, will the water level be higher, lower, or still the same?
|  |
 |
The Answer:
Click here!...
|  |
 |
Another Question:
In an aquarium filled with water, a block of ice block floats, with a bar of gold frozen in it.
We mark the current water level.
When the ice has molten completely and the bar of gold has sunk to the bottom of the aquarium,
will the water level be higher, lower, or still the same?
|  |
 |
A Hint :
Click here!...
|  |
 |
Another Answer:
Click here!...
|  |
 |
Yet Another Question:
In an aquarium filled with water, a block of wood floats.
On top of the block of wood, a brick has been glued.
We mark the current water level.
If the block of wood is turned around (so that the brick hangs under it), will the water level rise, fall, or stay the same?
|  |
 |
Yet Another Answer:
Click here!...
|  |
 |
The Fourth Question:
We have a pair of scales, with a block of lead on the left scale, and a block of wood on the right scale.
Both blocks have the same weight, so the scales are in balance.
We take the scales with the blocks and immerse them in an aquarium filled with water.
Will the scales stay in balance, will they turn left, or will they turn right?
|  |
 |
The Fourth Answer:
Click here!...
|  |
 |
The Fifth Question:
In an aquarium filled with water, a block of wood floats.
On top of the block of wood, there lies a bar of gold.
We mark the current water level.
If the bar of gold falls into the water and sinks to the bottom of the aquarium, will the water level rise, fall, or stay the same?
|  |
 |
The Fifth Answer:
Click here!...
|  |
 |
The Sixth Question:
In an aquarium filled with water, a spunge floats.
While the spunge slowly absorbs water (but keeps floating), will the water level rise, fall, or stay the same?
|  |
 |
The Sixth Answer:
Click here!...
|  |
|
back to the index
|  |
 |
The Bridge   
|  |
|  |
|
Four men want to cross a bridge. They all begin on
the same side. It is night, and they have only one flashlight with them.
At most two men can cross the bridge at a time, and any party who crosses,
either one or two people, must have the flashlight with them.
The flashlight must be walked back and forth: it cannot be thrown, etc.
Each man walks at a different speed. A pair must walk together at the speed
of the slower man. Man 1 needs 1 minute to cross the bridge, man 2 needs 2
minutes, man 3 needs 5 minutes, and man 4 needs 10 minutes. For example, if
man 1 and man 3 walk across together, they need 5 minutes.
|  |
 |
The Question:
How can all four men cross the bridge in 17 minutes?
|  |
 |
The Answer:
Click here!...
|  |
|
back to the index
|  |
 |
Alphabet Blocks   
|  |
|  |
|
Molly has a set of four alphabet blocks.
Each side of these blocks is printed with a different letter,
making 24 in total.
Molly notices that by rearranging the blocks,
she can spell each of the following words:
BOXY, BUCK, CHAW, DIGS, EXAM, FLIT,
GIRL, JUMP, OGRE, OKAY, PAWN, ZEST
|  |
 |
The Question:
Which letters are on each block?
|  |
 |
The Answer:
Click here!...
|  |
|
back to the index
|  |
 |
To Know or not To Know   
|  |
|  |
|
Two whole numbers, m and n, have been chosen.
Both are unequal to 1 and the sum of them is less than 100.
The product, m × n, is given to mathematician X.
The sum, m + n, is given
to mathematician Y. Then both mathematicians have the following conversation:
X: "I have no idea what your sum is, Y."
Y: "That's no news to me, X. I already knew you didn't know that."
X: "Ahah! Now I know what your sum must be, Y!"
Y: "And now I also know what your product is, X!"
|  |
 |
The Question:
What are the numbers m and n?
|  |
 |
The Answer:
Click here!...
|  |
 |
Another Question:
Thanks to Yiheng Wang, we can present you the following puzzle:
There is a professor with three of her equally highly intelligent students (Amy, Brad, and Charles) and they are playing a puzzle game. The professor puts a piece of paper on each student's forehead, and on each piece of paper there is a positive integer number. Each student can see the numbers on the other two students' foreheads, but not the one on him/herself. The professor tells the students: out of these three positive integer numbers, one number equals to the sum of the other two.
The students cannot speak until the professor starts to ask question and the three students answer in order.
Professor: "Do you know the number on your forehead (for sure, no guessing)?"
Amy: "I don't know."
Brad: "I don't know."
Charles: "I don't know."
Then the professor starts the second round of questioning.
Professor: "Do you know the number on your forehead (for sure, no guessing)?"
Amy: "I don't know."
Brad: "I don't know."
Charles: "Yes. It's 144."
Question to you, the reader: what are the three numbers?
|  |
 |
Another Answer:
Click here!...
|  |
|
back to the index
|  |
 |
The Masters Plaza   
|  |
|
Thanks to Hassan Issa from Lebanon, we can present you the following puzzle:
You have the chance to take your room in the "Masters Plaza",
a hotel in which 5 masters (5 of the most intelligent people who ever lived) are present.
The hotel consists of 5 rooms and a small restaurant that contains 5 tables.
Each master has a rank which shows his level of thinking with respect to the whole group.
The master with the first rank is said to be the head master, and he is not you.
Rooms, as well as tables, are successively numbered from 1 to 5 in a way that each master
lives in a room and eats on a table different in number from his rank.
To avoid confrontation, masters with successive ranks are neither allowed to live in rooms
next to each other nor to eat on tables next to each other.
The four present masters are: Albert Einstein, Galileo Galilei, Hassan Issa and Archimedes.
To have your room in the Plaza, you just have to know your rank, table number and room number knowing that:
- Archimedes doesn't eat on the fifth table.
- Einstein is not the head master.
- Archimedes has exactly the middle rank between Hassan and You.
- Einstein is more intelligent than Archimedes.
- Galileo eats on a table next to that of Einstein.
- Hassan does not eat on a table with the same number as his room number.
|  |
 |
The Question:
What are the ranks, room numbers, and table numbers of the five masters?
|  |
 |
The Answer:
Click here!...
Copyright © 2005 by Hassan Issa, Lebanon. Published on this website with permission.
|  |
|
back to the index
|  |
 |
3 Heads & 5 Hats   
|  |
|  |
|
In a small village in the middle of nowhere, three
innocent prisoners are sitting in a jail. One day, the cruel jailer
takes them out and places them in a line on three chairs, in such a way
that man C can see both man A and man B, man B
can see only man A, and man A can see none of the other men.
The jailer shows them 5 hats, 2 of which are black and 3 of which are white.
After this, he blindfolds the men, places one hat on each of their heads,
and removes the blindfolds again. The jailer tells his three prisoners that
if one of them is able to determine the color of his hat within one minute,
all of them are released. Otherwise, they will all be executed. None of the
prisoners can see his own hat, and all are intelligent. After 59 seconds,
man A shouts out the (correct) color of his hat!
|  |
 |
The Question:
What is the color of man A's hat, and how does he know?
|  |
 |
The Answer:
Click here!...
|  |
|
back to the index
|  |
 |
Coconut Chaos    
|  |
|  |
|
Five sailors survive a shipwreck and swim to a tiny island where there is nothing but a coconut tree and a monkey.
The sailors gather all the coconuts and put them in a big pile under the tree.
Exhausted, they agree to go to wait until the next morning to divide up the coconuts.
At one o'clock in the morning, the first sailor wakes up.
He realizes that he can't trust the others, and decides to take his share now.
He divides the coconuts into five equal piles, but there is
one coconut left over.
He gives that coconut to the monkey, hides his coconuts
(one of the five piles), and puts the rest of the coconuts
(the other four piles) back under the tree.
At two o'clock, the second sailor wakes up.
Not realizing that the first sailor has already taken his share,
he too divides the coconuts up into five piles,
leaving one coconut over which he gives to
the monkey.
He then hides his share (one of the five piles),
and puts the remainder (the other four piles) back under the tree.
At three, four, and five o'clock in the morning,
the third, fourth, and fifth sailors each wake up and carry out the same actions.
In the morning, all the sailors wake up, and try to look innocent.
No one makes a remark about the diminished pile of coconuts,
and no one decides to be honest and admit that they've
already taken their share.
Instead, they divide the pile up into five piles, for the sixth time,
and find that there is yet again one coconut left over, which they give to the monkey.
|  |
 |
The Question:
What is the smallest amount of coconuts that there could have been in the original pile?
|  |
 |
The Answer:
Click here!...
|  |
|
back to the index
|  |
 |
Numbers and Dots    
|  |
|  |
|
This is a famous problem from 1882, to which a prize of $1000 was
awarded for the best solution. The task is to arrange the seven
numbers 4, 5, 6, 7, 8, 9, and 0, and eight dots in such a way that
an addition approximates the number 82 as close as possible.
Each of the numbers can be used only once. The dots can be used in
two ways: as decimal point and as symbol for a recurring decimal.
For example, the fraction 1/3 can be written as
The dot on top of the three denotes that this number is repeated
infinitely. If a group of numbers needs to be repeated, two dots are
used: one to denote the beginning of the recurring part and one to
denote the end of it. For example, the fraction
1/7 can be written as
Note that '0.5' is written as '.5'.
|  |
 |
The Question:
How close can you get to the number 82?
|  |
 |
The Answer:
Click here!...
|  |
|
back to the index
|  |
|  |
 |